An angle modulated signal is defined as $s (t) = 100 c o s [2 π f_{c} t + t \int - \infty m (τ) d τ]$ . The message signal m(t) is shown in the figure below.

If $f_{c}$ is the carrier frequency, then the maximum frequency deviation of s(t) will be Hz.

1.6

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Solution

The correct option is A 1.6

$S (t) = 100 c o s [2 π f_{c} t + t \int - \infty m (τ) d τ]$

$θ (t) = 2 π f_{c} t + t \int - \infty m (τ) d τ$

$f_{i} = \frac{1}{2 π} \frac{d θ (t)}{d t} = f_{c} + \frac{1}{2 π} m (t)$

$Δ f_{m a x} = | f_{i} - f_{c} |_{m a x} = \frac{1}{2 π} | m (t) |_{m a x} = \frac{10}{2 π} H z \approx 1.60 H z$

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An angle modulated signal is defined as s(t)=100cos[2πfct+t∫−∞m(τ)dτ]. The message signal m(t) is shown in the figure below. If fc is the carrier frequency, then the maximum frequency deviation of s(t) will be Hz. 1.6

The correct option is A 1.6 S(t)=100cos[2πfct+t∫−∞m(τ)dτ] θ(t)=2πfct+t∫−∞m(τ)dτ fi=12πdθ(t)dt=fc+12πm(t) Δfmax=|fi–fc|max=12π|m(t)|max=102πHz≈1.60 Hz

An angle modulated signal is defined as $s (t) = 100 c o s [2 π f_{c} t + t \int - \infty m (τ) d τ]$ . The message signal m(t) is shown in the figure below.

If $f_{c}$ is the carrier frequency, then the maximum frequency deviation of s(t) will be Hz.

1.6