MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Magnetic Dip

An angle of d...

Question

An angle of dip at the magnetic equator is

A

0^{0}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

45^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

90^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0^{0}$
At magnetic equator $B_{V} = 0$
therefore, angle of dip which is given by
$tan ϕ = B_{V} / B_{H} = 0$
$ϕ = 0^{o}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. If a magnet is suspended at an angle

30^{\circ}

to the magnetic meridian, it makes an angle of 45o with the horizontal. The real dip is

Q. At a place, a freely suspended magnet shows a dip angle of

30^{0}

. If the plane of the magnet is at an angle of

45^{0}

from the magnetic meridian, then the real dip of the magnet will be

Q. If a magnet is suspended at an angle

30^{o}

to the magnetic meridian, the dip needle makes an angle of

45^{o}

with the horizontal. The real dip is:

Q. At two different places the angles of dip are respectively

30^{0}

45^{0}

. At these two places the ratio of horizontal component of earths magnetic field is

Q. Assume the dipole model for earth's magnetic field B which is given by the vertical component of magnetic field,

B_{v} = \frac{μ_{0}}{4 π} \frac{2 m c o s θ}{r^{3}}

and the horizontal component of magnetic field is

B_{H} = \frac{μ_{0}}{4 π} \frac{m s i n θ}{r^{3}}

θ = 90^{0}

- latitude as measured from magnetic equator, then the loci of point for which dip angle is

45^{0}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Characterising Earth’s Field

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon