Question

An angle 'x' is ${14}^{\circ }$ more than its complement. Find the angle.

• A. 38°
• B. 52°
• C. 50°
• D. 104^o

Answer 1

The correct option is B

52°

Let the angle be x.

The sum of two complementary angles is ${90}^{\circ }$

So the second angle will be $({90}^{\circ }-x)$

So, $x-({90}^{\circ }-x)={14}^{\circ }$

$\Rightarrow x-{90}^{\circ }+x={14}^{\circ }$

$\Rightarrow 2x={104}^{\circ }$

$\Rightarrow x={52}^{\circ }$