Question

An angle 'x' is 14${}^{\circ }$ more than its complement. Find the angle.

• A. 38${}^{\circ }$
• B. 52${}^{\circ }$
• C. 50${}^{\circ }$
• D. 104${}^{\circ }$

Answer 1

The correct option is B

52${}^{\circ }$

The sum of two complementary angles is 90${}^{\circ }$.

If one angle is x, then another angle will be ${90}^{\circ }-x$.
$\Rightarrow x-({90}^{\circ }-x)={14}^{\circ }$
$\Rightarrow 2x={104}^{\circ }$
$\Rightarrow x={52}^{\circ }$