An anion $X^{3 -}$ has 36 electrons and 45 neutrons . What is the mass no. of the element X?

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Solution

The correct option is C 78
Since the anion has a net charge of $- 3$ ,

$n_{e} - n_{p} = 3$
$\to n_{p} = 36 - 3 = 33$

Therefore, mass of element X= $n_{p} + n_{n} = 45 + 33 = 78 a m u$

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