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Question

An annular circular brass disk of inner radius r and outer radius R is rotating about an axis passing through its center and perpendicular to its plane with a uniform angular velocity ω in a uniform magnetic field of induction B normal to the plane of the disk. The induced emf between the inner and the outer edge of the annular disk is :

A
Bω(r2+R2)2
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B
Bω(R2r2)2
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C
Bω(rR)2
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D
Bω(r+R)2
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Solution

The correct option is B Bω(R2r2)2
d(emf)=Bwxdx
emf=RrBwxdx
=BwRrx22
=Bw(R2r22)
Emf between inner and outer edge will be
=Bw(R2r22)

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