An ant first travels from P to R on a right angled triangle PQR which is 13m long. Then it walks to point Q travelling 12m. Find the displacement and distance travelled by the ant?

Displacement: 25m , Distance: 25m

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Displacement: 25m , Distance: 5m

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Displacement: 5m , Distance: 25m

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Displacement: 5m , Distance: 5m

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Solution

The correct option is C
Displacement: 5m , Distance: 25m

Total Distance Travelled = PR + RQ = 13 + 12 = 25m
Initial position is P and final position is Q.
And as we know length between initial and final position is Displacement.
Total Displacement = PQ = $\sqrt{13^{2} - 12^{2}}$ = 5m (using pythagoras theorem)

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An ant travels along a right angled triangle $△$ PQR first from P to R, then from R to Q. Find the displacement and distance travelled by the ant?
Given, PR = $13 m$ , RQ = $12 m$

Q. An ant first travels from P to R which is 13 m long and then it walks to point Q which is 12 m, on a right angled triangle PQR. The distance travelled by the ant is

Q. An ant first travels from P to R which is 13 m long and then it walks to point Q which is 12 m, on a right angled triangle PQR. The displacement of the ant is

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An ant first travels from P to R on a right angled triangle PQR which is 13m long. Then it walks to point Q travelling 12m. Find the displacement and distance travelled by the ant?

The correct option is C Displacement: 5m , Distance: 25m Total Distance Travelled = PR + RQ = 13 + 12 = 25m Initial position is P and final position is Q. And as we know length between initial and final position is Displacement. Total Displacement = PQ = √132−122 = 5m (using pythagoras theorem)