An ant first travels from $P$ to $R$ on a right-angled triangle $P Q R$ which is 13m long. Then it walks to point $Q$ travelling 12m. Find the displacement and distance travelled by the ant?

Displacement: 25m , Distance: 25m

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Displacement: 25m , Distance: 5m

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Displacement: 5m , Distance: 25m

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Displacement: 5m , Distance: 5m

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Solution

The correct option is C
Displacement: 5m , Distance: 25m

Total Distance Travelled $= P R + R Q = 13 + 12 = 25 m$
Initial position is $P$ and final position is $Q$ .

Shortest distance length between initial and final position is displacement.

Total Displacement $= P Q = \sqrt{13^{2} - 12^{2}} = 5 m$ (using pythagoras theorem)

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Q. An ant first travels from P to R which is 13 m long and then it walks to point Q which is 12 m, on a right angled triangle PQR. The distance travelled by the ant is

Q. An ant first travels from P to R which is 13 m long and then it walks to point Q which is 12 m, on a right angled triangle PQR. The displacement of the ant is

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An ant first travels from P to R on a right-angled triangle PQR which is 13m long. Then it walks to point Q travelling 12m. Find the displacement and distance travelled by the ant?

The correct option is C Displacement: 5m , Distance: 25m Total Distance Travelled =PR+RQ=13+12=25m Initial position is P and final position is Q. Shortest distance length between initial and final position is displacement. Total Displacement =PQ=√132−122=5m (using pythagoras theorem)

An ant first travels from $P$ to $R$ on a right-angled triangle $P Q R$ which is 13m long. Then it walks to point $Q$ travelling 12m. Find the displacement and distance travelled by the ant?