An ant moves along the square loop of side am. If it moves along path ABC, starting from A to reach at the point C in 2s.
The average velocity of ant will be
A
Avergae velocity of ant is am/s along ABC
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B
Avergae velocity of ant is a√2m/s along AC
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C
Avergae velocity of ant is 3a√2m/s along BC
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D
Average velocity of ant is zero.
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Solution
The correct option is B Avergae velocity of ant is a√2m/s along AC The displacement of ant will be the length of diagonal AC. ΔS=AC=√2am Δt=2s velocityavg=ΔSΔt ∴velocityavg=√2am2s=a√2m/s This is the required magnitude of average velocity. However, the direction of average velocity will be along the direction of displacement(A→C). ⇒ Avergae velocity of ant is a√2m/s along AC