An ant travels along a right angled triangle △ PQR first from P to R, then from R to Q. Find the displacement and distance travelled by the ant?
Given, PR = 13m, RQ = 12m
A
Displacement = 25m
Distance = 25m
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B
Displacement = 25m
Distance = 5m
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C
Displacement = 5m
Distance = 25m
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D
Displacement = 5m
Distance =5m
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Solution
The correct option is C Displacement = 5m
Distance = 25m Given, the distance PR = 13m, and RQ = 12m ∴ the total distance travelled = PR + RQ = 13+12 = 25m.
The initial position is P, and the final position is Q.
The shortest distance between the initial and the final positions is the displacement. ∴ the total displacement = PQ = √132−122 = √25 = 5m (using Pythagoras theorem) ∴ the distance covered by the ant is 25m, and the displacement is 5m.