An antimony ball of volume 15cm3 is heated to 210∘C which caused the volume to become 15.045cm3, if γ for antimony is 15×10−6∘C−1, what is the initial temperature of the ball?
A
10∘C
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B
15∘C
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C
30∘C
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D
55∘C
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Solution
The correct option is A10∘C Given: The coefficient of cubical thermal expansion for the antimony ball, γSb=15×10−6∘C−1 The final temperature of the ball, Tf=210∘C Let the initial temperature be Ti∘C Change in the volume, ΔV=15.045−15=0.045cm3 We know that γ=ΔVV0×ΔT, where V0 is the initial volume, and ΔT is the rise in the temperature =Tf−Ti