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Question

An antimony ball of volume 15 cm3 is heated to 210 C which caused the volume to become 15.045 cm3, if γ for antimony is 15×106 C1, what is the initial temperature of the ball?

A
10 C
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B
15 C
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C
30 C
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D
55 C
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Solution

The correct option is A 10 C
Given:
The coefficient of cubical thermal expansion for the antimony ball, γSb=15×106 C1
The final temperature of the ball, Tf=210 C
Let the initial temperature be Ti C
Change in the volume, ΔV=15.04515=0.045 cm3
We know that
γ=ΔVV0×ΔT, where V0 is the initial volume, and ΔT is the rise in the temperature =TfTi

ΔT=ΔVV0γ=0.04515×15×106

ΔT=200 C
TfTi=210Ti=200 C
Ti=210200=10 C

The initial temperature of the ball was 10 C.

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