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Question

An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.

A
64
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B
72
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C
78
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D
80
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Solution

The correct option is B 64
Let a and d be the first term and common difference of the given AP.
Given,n=50, last term =106,a3=12

By using formula for nth term tn=a+(n1)d

a+2d=12 ...(1)

a+49d=106 ...(2)

On subtracting (1) from (2), we get

47d=94d=2

Putting d=2 in (1), we get

a=122×2=8

Now, a29=a+28d=8+28×2=64

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