The correct option is D 12
We know that sum to n terms of an AP is n2(a+l), where a and l are the first and last terms respectively, and n is the number of terms.
Given that an AP has four terms, first and last terms are 1 and 5 respectively.
n=4,a=1,l=5
Sn=n(a+l)2
Sn=4(1+5)2
Sn=12