An apple falls from a tree because of gravitational attraction between the earth and apple. If $F_{1}$ is the magnitude of force exerted by the earth on apple and $F_{2}$ is the magnitude of force exerted by apple on the earth, then:

F_{1}

>

F_{2}

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F_{1}

=

F_{2}

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F_{1}

=

F_{2}

0

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F_{1}

<

F_{2}

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Solution

The correct option is B $F_{1}$ $=$ $F_{2}$
According to Newton's universal law of gravitation, the gravitational force between two masses $m_{1}$ and $m_{2}$ separated by a distance $d$ is given by:
$F = \frac{G m_{1} m_{2}}{d^{2}}$

This gravitational force acts along the line joining the two masses which are equal in magnitude but opposite in direction.

Therefore, the force exerted by apple on the Earth and the force exerted by the Earth on apple are equal in magnitude.

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An apple of mass 100 g falls from a tree because of gravitational attraction between the earth and the apple. If the magnitude of force exerted by the earth on the apple be $F_{1}$ and the magnitude of force exerted by the apple on the earth be $F_{2}$ , then :
(a) $F_{1}$ is very much greater than $F_{2}$
(b) $F_{2}$ is very much greater than $F_{1}$
(c) $F_{1}$ is only a little greater than $F_{2}$
(d) $F_{1}$ and $F_{2}$ are exactly equal

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An apple falls from a tree because of gravitational attraction between the earth and apple. If F1 is the magnitude of force exerted by the earth on apple and F2 is the magnitude of force exerted by apple on the earth, then:

An apple falls from a tree because of gravitational attraction between the earth and apple. If $F_{1}$ is the magnitude of force exerted by the earth on apple and $F_{2}$ is the magnitude of force exerted by apple on the earth, then: