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Standard Electrode Potentials

An aqueous bl...

Question

An aqueous blue coloured solution of a transition metal nitrate reacts with $H_{2} S$ in acidic medium to give a black precipitate (X), which dissolves in $K C N$ solution forming a clear solution of (Y). The blue solution on reaction with $K I$ in weakly acidic medium becomes intensely brown and produces a white precipitate (Z).

The electron configuration of the transition metal ion is

A

[A r] 3 d^{9}

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B

[A r] 3 d^{10}

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C

[K r] 4 d^{9}

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D

[K r] 4 d^{10}

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Solution

The correct options are
A $[A r] 3 d^{9}$
B $[A r] 3 d^{10}$
C $[K r] 4 d^{9}$
The general electronic configuration of transition metals is $[A r] 3 d^{1 - 10} 4 s^{1 - 2}$ for first transition series and
$[K r] 4 d^{1 - 10} 5 s^{0 - 2}$ for second transition series.
When some electrons are lost, ions are obtained.
Hence, the electronic configurations $[A r] 3 d^{9}$ , $[A r] 3 d^{10}$ and $[K r] 4 d^{9}$ refer to transition metal ions.

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