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Oxidizing and Reducing Character of Halogens

An aqueous so...

Question

An aqueous solution containing 1 mol of HgI $_{2}$ and 2 mol of NaI is orange in color. On addition of excess NaI, the solution becomes colorless. The orange color reappears on subsequent addition of NaOCl. Explain with equation.

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Solution

The solution having 1 mole of $H g I_{2}$ and 2 moles of $N a I$ is orange in colour due to the partial solubility of $H g I_{2}$ . On addition of excess $N a I$ , the colourless complex $N a_{2} H g I_{4}$ is formed.
$H g I_{2} + 2 N a l \to N a_{2} H g I_{4}$ .
The $N a_{2} H g I_{4}$ on addition of $N a O C l$ oxidizes as .
$3 N a_{2} H g I_{4} + 2 N a O C l + 2 H_{2} O \to 3 H g I_{2} + 2 N a l_{3} + 4 N a O H + 2 N a C l$
So, colour of partially soluble $H g I_{2}$ reappeares.

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