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Standard XII

Chemistry

Ideal Gas Law

An aqueous so...

Question

An aqueous solution containing $2.14$ g $K I O_{3}$ was treated with $100$ ml of $0.4 M K I$ solution, the weight of $I_{2}$ produced is :

6.096

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7.620

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30.480

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18.288

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Solution

The correct option is A $6.096$ g
$2.14$ g of $K I O_{3}$ corresponds to $\frac{2.14}{214} = 0.01$ moles.
$100$ ml of $0.4 M K I$ solution corresponds to $\frac{100}{1000} \times 0.4 = 0.04$ moles.
$0.001$ moles of $K I O_{3}$ will give $0.005$ moles of $K I$ .
However, only $0.04$ moles of $K I$ are present.
Thus, $K I$ is the limiting reagent.
Mass of iodine obtained is $0.04 \times \frac{3}{5} \times 254 = 6.096$ g.

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An aqueous solution containing 2.14 g KIO3 was treated with 100 ml of 0.4MKI solution, the weight of I2 produced is :

An aqueous solution containing $2.14$ g $K I O_{3}$ was treated with $100$ ml of $0.4 M K I$ solution, the weight of $I_{2}$ produced is :