An aqueous solution containing 288 gm of a non- volatile compound having the stoichiometric composition CxH2xOx in 90 gm water boils at 101-24-C- at 1-00 atmospheric pressure- If the molecular formula is CxHyOz KbH2O-0-512 K mol-1kg TbH2O-100-C- Find the value of x-y-z-

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Van't Hoff Factor

An aqueous so...

Question

An aqueous solution containing 288 gm of a non- volatile compound having the stoichiometric composition $C_{x} H_{2 x} O_{x}$ in 90 gm water boils at ${101.24}^{\circ}$ C. at 1.00 atmospheric pressure. If the molecular formula is $C_{x} H_{y} O_{z}$ $K_{b} (H_{2} O) = 0.512 K m o l^{- 1} k g$ $T_{b} (H_{2} O) = 100^{\circ} C$ . Find the value of $x + y + z$ ?

168

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176

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180

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None of these

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Solution

The correct option is A $176$
The elevation in the boiling point $Δ T_{b} = 101.24 - 100 = {1.24}^{o} C$
$Δ T_{b} = K_{b} m$
$1.24 = 0.512 m$
$m = 2.422$
Here m is the molality
The molality of the solution $m = \frac{mass of solute}{molar mass of solute \times mass of solvent (in kg)} = \frac{288}{M \times 0.090}$
The molar mass of solute $M = 1321 g / m o l$
From molecular formula $C_{x} H_{2 x} O_{x}$ the molar mass is $12 x + 2 x + 16 x = 30 x$
Hence, $30 x = 1321$
$x = 44$
Hence, $x + 2 x + x = 4 x = 4 (44) = 176$

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An aqueous solution containing 288 gm of a non- volatile compound having the stoichiometric composition CxH2xOx in 90 gm water boils at 101.24∘C. at 1.00 atmospheric pressure. If the molecular formula is CxHyOz Kb(H2O)=0.512Kmol−1kgTb(H2O)=100∘C. Find the value of x+y+z?