Question

An aqueous solution containing $6.5g$ of $NaCl$ of $90\%$ purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid $NaOH$. The volume of $1M$ acetic acid required to neutralise $NaOH$ obtained above is

• A. $2000c{m}^3$
• B. $100c{m}^3$
• C. $200c{m}^3$
• D. $1000c{m}^3$

Answer 1

The correct option is B $100c{m}^3$

Weight of pure $NaCl=6.5\times 0.9=5.85g$

No. of equivalence of $NaCl$ = $5.85/58.5=0.1$

No. of equivalence of $NaOH$ obtained = 0.1 Volume of 1 M acetic acid required for the neutralisation of $NaOH=\frac{0.1\times 1000}{1}=100c{m}^3$