Question

An aqueous solution containing $V^{x+}$ ion has magnetic moment equal to $\sqrt{15}BM$. Therefore, the x is:

• A. $5$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$2$

Let $n$ be the number of unpaired electrons.

Magnetic moment $=\sqrt{n(n+2)}=\sqrt{15}$

$\Rightarrow n=3$

Atomic number of Vanadium is $23$. So, it must loose all its $4s$ electrons to get $3$ unpaired d electrons.

$\therefore$ value of $x$ will be $2$