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Enthalpy

An aqueous so...

Question

An aqueous solution of 0.1 molal concentration of surcose should have freezing point of: $(K_{f} = 1.86 K m o l^{- 1} k g)$

{0.186}^{o} C

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{1.86}^{o} C

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- {1.86}^{o} C

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- {0.186}^{o} C

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Solution

The correct option is D $- {0.186}^{o} C$
The value of freezing point is $- {0.186}^{o} C$
$Δ T_{f} = \frac{1000 \times K_{f} \times w}{m \times W} = K_{f} \times m o l a l i t y$
$= 1.86 \times 0.1 = 0.186$
Thus, $f . p t . = 0 - {0.186}^{o} C = - {0.186}^{o} C$

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