Question

An aqueous solution of $6.3g$ of oxalic acid dihydrate is made upto $250\text{ml}$.The volume (in ml) of $0.1\text{N NaOH}$ required to complete neutralize $10\text{ml}$ of this solution is:

• A. $40mL$
• B. $30mL$
• C. $20mL$
• D. $10mL$

Answer 1

The correct option is A $40mL$

$\text{Normality of oxalic acid =}\frac{6.3\times 1000}{63\times 250}=0.4N$
$N_1{V}_1=N_2{V}_2$
$10\times 0.4=0.1\times V$
$\Rightarrow V=\frac{10\times 0.4}{0.1}=40mL$