An aqueous solution of a non-electrolyte solute boils at $100.5 2^{0} C$ . The freezing point of the solution will be?

0^{0} C

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- {1.86}^{0} C

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{1.86}^{0} C

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None of the above

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Solution

The correct option is C $- {1.86}^{0} C$
The correct answer is B.

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Similar questions

An aqueous solution of a non-electrolyte boils at 100.52°C. The freezing point of the solution will be

- {0.52}^{o} C .

K_{f} = {1.86}^{0} C / m

- {1.86}^{0} C

- {0.14}^{\circ} C

[k_{f} (H_{2} O) = 1.86 K k g m o l^{- 1}]

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