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Standard XII

Chemistry

Hydrogen Peroxide

An aqueous so...

Question

An aqueous solution of an unknown compound $(X)$ gives the following reactions.
(i) It gives brown precipitate with alkaline $K M n O_{4}$ solution.
(ii) It forms $H C l$ and evolves $O_{2}$ when reacted with $C l_{2}$ gas.
(iii) It liberates $l_{2}$ from an acidified $K l$ solution.
(iv) It gives orange yellow colour with acidified titanic sulfate solution.
Identify $(X)$ .

X = H_{2} O_{2}

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X = H_{2} O

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X = H_{2} O_{3}

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none of the above

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Solution

The correct option is D $X = H_{2} O_{2}$
The unknown compound $X$ is hydrogen peroxide $H_{2} O_{2}$ .
(1) It gives brown ppt. of $M n O_{2}$ with alkaline $K M n O_{4}$ solution. $2 K M n O_{4} + 3 H_{2} O_{2} \to 2 M n O_{2} + 3 O_{2} + 2 H_{2} O + 2 K O H$ .
(2) On reaction with chlorine, hydrogen peroxide forms $H C l$ and oxygen. $C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}$ .
(3) On reaction with acidified $K I$ solution, hydrogen peroxide liberates iodine. $2 K I + H_{2} O_{2} \to 2 K O H + I_{2}$ .
(4) With acidified titanic sulphate solution, hydrogen peroxide gives orange yellow colour. $T i (S O_{4})_{2} + H_{2} O_{2} H_{2} S O_{4} - --- \to H_{2} [T i O_{2} (S O_{4})_{2}] per titanic acid$ .

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