Question

An aqueous solution of $FeC{l}_3$ (formula mass = 162) has a density of 1.1 g $m{l}^{–1}$ and contains $20\%$ $FeC{l}_3$. Molarity of this solution is-

• A. 0.028 M
• B. 0.163 M
• C. 0.2 M
• D. 1.36 M

Answer 1

The correct option is D 1.36 M

100 gm solution contains 20 gm $FeC{l}_3$
Volume of solution = $\frac{100}{1.1}$ ml
$n_{FeC{l}_3}=\frac{20}{162}$
Molarity(M) = $\frac{\frac{20}{162}}{\frac{100}{1.1}}\times 1000=1.36M$