Question

An aqueous solution of glucose is $10\%$ In strength. The volume in which one gram mole of it is dissolved will be

• A. $18$ liter
• B. $9$ liter
• C. $0.9$ liter
• D. $1.8$ liter

Answer 1

The correct option is A $18$ liter

10% glucose strength means, in 100g of solution 10g is glucose and 90g is water.

Therefore, number of moles of glucose=$\frac{10g}{180g/mol}$

Hence, $\frac{1}{18}mol$ of glucose is dissolved in 0.1L solution

Therefore, one gram mole of glucose is dissolved in=$\frac{0.1\times 182}{10}=1.8L$