Question

An aqueous solution of glucose is 26% (w/v). Find the volume in which 1 g mole of it is dissolved. (Formula of glucose is $C_6{H}_{12}{O}_6$).

Answer 1

$1$ mole of glucose $=180g$

$\frac{26}{100}=\frac{180}{weight/volumeofsolution}$

Volume of solution $=\frac{180\times 100}{26}=692.3$ ml