Question

An aqueous solution of methyl alcohol contains 48 g of alcohol. The mole fraction of alcohol is 0.6 . The weight of water in the solution is:

• A. $27g$
• B. $2.7g$
• C. $18g$
• D. $1.8g$

Answer 1

The correct option is C $18g$

Methyl alcohol $=C{H}_{3}OH$

$X_{alcohol}=\frac{n_{alcohol}}{n_{alcohol}+n_{water}}$

$⟹0.6=\frac{\frac{48}{32}}{\frac{48}{32}+\frac{X}{18}}$

$⟹\frac{X}{18}=1$

$⟹X=18gm$

Hence, the correct option is $\text{C}$