An aqueous solution of sodium cyanide has a $p H$ of approximately:

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6.5

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11.5

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4.8

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Solution

The correct option is C 11.5
$N a C N$ will undergo hydrolysis.
$C N^{-} + H_{2} O \to H C N + O H^{-}$
$∴$ solution turns basic, therefore $p H > 7$
Only one option $\to$ 11.5

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