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Standard XII

Chemistry

Coordination Complexes

An aqueous so...

Question

An aqueous solution of titanium chloride, when subjected to magnetic measurement, measured zero magnetic moment.

Assuming the complex as octahedral in aqueous solution, the formula of the complex is :

[T i (H_{2} O)_{6}] C l_{2}

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[T i (H_{2} O)_{6}] C l_{4}

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[T i C l_{6}]^{3 -}

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[T i (H_{2} O)_{4} C l_{2}]

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Solution

The correct option is C $[T i (H_{2} O)_{6}] C l_{4}$
As we know,magnetic moment
$μ = \sqrt{n (n + 2)} = 0$ BM
so it have zero unpaired electron,

also as complex is octahedral so co-ordination no. is 6
$T i^{+ 4}$ exists and complex is $[T i (H_{2} O)_{6}] C l_{4}$
+4 CN = 6

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Similar questions

Q. An aqueous solution of titanium chloride, when subjected to magnetic measurement, measured zero magnetic moment. Assuming the octahedral complex in aqueous solution, the formulae of the complex is :

Q. Addition of excess aqueous ammonia to a pink coloured aqueous solution of

M C l_{2} .6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex `I behaves as I :3 electrolyte. The reaction of X with excess HCI at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M.. whereas it is zero for complex Y.
Among the following options, which statements is(are) CORRECT ?

Q. The addition of excess aqueous ammonia to a pink coloured aqueous solution of

C o C l_{2} .6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex

Y

in the presence of air. In an aqueous solution, complex

Y

behaves as

1 : 3

electrolyte. The reaction of

X

with excess

H C l

at room temperature results in the formation of a blue colored complex

Z

([C o C l_{4}]^{2 -})

. The calculated spin only magnetic moment of

X

and

Z

3.87 BM

whereas, it is zero for complex

Y

.
Choose the correct statement among the following.

Q. Addition of excess aqueous ammonia to a pink coloured aqueous solution of

M C l_{2} .6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 :3 electrolyte. The reaction of X with excess

H C l

at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for the complex Y. Among the following options, which statement(s) is/are correct?

Addition of excess aqueous ammonia to a pink coloured aqueous solution of $M C l_{2} . H_{2} O (x) a n d N H_{4} C l$ gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1:3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y.
Among the following options, which statemet(s) is (are) correct?

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An aqueous solution of titanium chloride, when subjected to magnetic measurement, measured zero magnetic moment. Assuming the complex as octahedral in aqueous solution, the formula of the complex is :

The correct option is C [Ti(H2O)6]Cl4As we know,magnetic momentμ=√n(n+2)=0 BMso it have zero unpaired electron,also as complex is octahedral so co-ordination no. is 6 Ti+4 exists and complex is [Ti(H2O)6]Cl4 +4 CN = 6

An aqueous solution of titanium chloride, when subjected to magnetic measurement, measured zero magnetic moment.

Assuming the complex as octahedral in aqueous solution, the formula of the complex is :

The correct option is C $[T i (H_{2} O)_{6}] C l_{4}$
As we know,magnetic moment
$μ = \sqrt{n (n + 2)} = 0$ BM
so it have zero unpaired electron,

also as complex is octahedral so co-ordination no. is 6
$T i^{+ 4}$ exists and complex is $[T i (H_{2} O)_{6}] C l_{4}$
+4 CN = 6