An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

Open in App

Solution

Net charge on a dipole $= - q + q = 0$ .

According to Gauss's theorem, electric flux through the surface,
$= \frac{q}{ϵ_{0}} = \frac{0}{ϵ_{0}} = 0$ .

Suggest Corrections

Similar questions

20 \times 10^{- 6} C

1 c m

An electric dipole is an arrangement of two equal charges of equal magnitude but opposite nature, separated by some fixed distance.

Now consider a dipole enclosed inside a closed surface S. The flux through the surface S is zero.

μ

Join BYJU'S Learning Program