An arc bridge has the following constants- Arm AB - Capacitor of 0-5 - F in parallel with 1 k- resistance-Arm AD - Resistance of 2 k-Arm BC - Capacitor of 0-5 - FArm CD - Unknown capacitor of Cx and resistance Rx in series-Frequency - 1 kHzThe dissipation factor is

nbsp; nbsp;R_x=C_1C_3R_2=0.5μ F0.5μ F× 2k=2 kΩ nbsp; nbsp;C_x=R_1R_2×C_3=1k2k× 0.5μ F=0.25 μ F The dissipation factor is given by, nbsp; n ...

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Byju's Answer

Standard XII

Physics

V-I Characteristics for a P-N Junction Diode

An arc bridge...

Question

An arc bridge has the following constants:
Arm AB - Capacitor of $0.5 μ F$ in parallel with $1 k Ω$ resistance.
Arm AD - Resistance of $2 k Ω$
Arm BC - Capacitor of $0.5 μ F$
Arm CD - Unknown capacitor of $C_{x}$ and resistance $R_{x}$ in series.
Frequency - 1 kHz
The dissipation factor is

3.14

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1.05

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6.28

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0.57

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Solution

The correct option is A 3.14

$R_{x} = \frac{C_{1}}{C_{3}} R_{2} = \frac{0.5 μ F}{0.5 μ F} \times 2 k = 2 k Ω$

$C_{x} = \frac{R_{1}}{R_{2}} \times C_{3} = \frac{1 k}{2 k} \times 0.5 μ F = 0.25 μ F$

$The dissipation factor is given by,$

$D = ω R_{x} C_{x}$
$= 2 \times 3.142 \times 1000 \times 2 \times 1000 \times 0.25 \times 10^{- 6}$

$= 3.142$

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An arc bridge has the following constants: Arm AB - Capacitor of 0.5μF in parallel with 1kΩ resistance. Arm AD - Resistance of 2kΩ Arm BC - Capacitor of 0.5μF Arm CD - Unknown capacitor of Cx and resistance Rx in series. Frequency - 1 kHz The dissipation factor is

The correct option is A 3.14 Rx=C1C3R2=0.5μF0.5μF×2k=2kΩ Cx=R1R2×C3=1k2k×0.5μF=0.25μF The dissipation factor is given by, D=ωRxCx =2×3.142×1000×2×1000×0.25×10−6 =3.142

An arc bridge has the following constants:
Arm AB - Capacitor of $0.5 μ F$ in parallel with $1 k Ω$ resistance.
Arm AD - Resistance of $2 k Ω$
Arm BC - Capacitor of $0.5 μ F$
Arm CD - Unknown capacitor of $C_{x}$ and resistance $R_{x}$ in series.
Frequency - 1 kHz
The dissipation factor is