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Standard XII

Chemistry

1900's Physics and Wave

An archaeolog...

Question

An archaeologist analyses the wood in a prehistoric structure and finds that $C^{14}$ (Half life $= 5700$ years) to $C^{12}$ is only one-fourth of that found in the cells of buried plants. What is the age of the wood ?

5700 y e a r s

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2850 y e a r s

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11, 400 y e a r s

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22, 800 y e a r s

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Solution

The correct option is C $11, 400 y e a r s$
$\frac{C_{14}}{C_{12}} = \frac{1}{4} = {(\frac{1}{2})}^{t / 5700} \Rightarrow \frac{t}{5700} = 2 \Rightarrow t = 11400 y e a r s$

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An archaeologist analyses the wood in a prehistoric structure and finds that C14 (Half life=5700 years) to C12 is only one-fourth of that found in the cells of buried plants. What is the age of the wood ?

The correct option is C 11,400yearsC14C12=14=(12)t/5700⇒t5700=2⇒t=11400 years

An archaeologist analyses the wood in a prehistoric structure and finds that $C^{14}$ (Half life $= 5700$ years) to $C^{12}$ is only one-fourth of that found in the cells of buried plants. What is the age of the wood ?

The correct option is C $11, 400 y e a r s$
$\frac{C_{14}}{C_{12}} = \frac{1}{4} = {(\frac{1}{2})}^{t / 5700} \Rightarrow \frac{t}{5700} = 2 \Rightarrow t = 11400 y e a r s$