Question

An arithmetic sequence starts $23,36,49,62,...$ What is the term of the sequence to exceed $100000$?

Answer 1

$a=23d=36-23=13$

$a+(n-1)d>100000$

$23+(n-1)13>100000$

$13n-13>99977$

$13n=99990$

$n>7691.53$

${7692}^{nd}$ term will be $>100000$.