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Question
An army contingent of 616 members is to march behind an army band of 32 members in parade. The two groups are to march in the same number of columns. What is the maxiumum number of columns in which they can march?
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Solution
We are given that an army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. We need to fund the maximum number of columns in which they can march.
Members in army = 616
Members in band = 32.
Therefore, Maximum number of columns = H.C.F of 616 and 32.
By applying Euclid’s division lemma
616 = 32 x 19 + 8
32 = 8 x 4 + 0.
Therefore, H.C.F. = 8
Hence, the maximum number of columns in which they can march is 8
We are given that an army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. We need to fund the maximum number of columns in which they can march.
Members in army = 616
Members in band = 32.
Therefore, Maximum number of columns = H.C.F of 616 and 32.
By applying Euclid’s division lemma
616 = 32 x 19 + 8
32 = 8 x 4 + 0.
Therefore, H.C.F. = 8
Hence, the maximum number of columns in which they can march is 8
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