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Synthesis by Reduction of Nitro Compounds

An aromatic c...

Question

An aromatic compound $(C_{7} H_{8} O_{2})$ gives coloured solution with neutral $F e C l_{3}$ solution and a white turbidity with Lucas reagent. Mention the respective numbers of positional isomers $(X)$ and the number of moles $(Y)$ of $H_{2}$ liberated in the following reaction.
$C_{7} H_{8} O_{2} (1 m o l) N a - -- \to e x c e s s$ .
Write the answer in form of $(X + Y)$ .

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Solution

$C_{7} H_{8} O_{2} N e u t r a l \to F e C l_{3} (A) + v e$
So, (A) must contain-phenols & alcoholic group.
Two positional isomer $x = 2$
$y = 2$
$x + y = 4$ .

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