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Standard XII

Chemistry

Optical Activity

An aromatic c...

Question

An aromatic compound has molecular formula $C_{7} H_{7} B r$ . Give the possible isomers and the appropriate method to distinguish them

3 isomer; by heating with

A g {N O}_{3}

solution

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4 isomer; by treating with

A g {N O}_{3}

solution

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4 isomers; by oxidation

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5, isomers; by oxidation

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Solution

The correct option is C 4 isomers; by oxidation
Four isomers are possible. They can be separated by oxidation. Different isomers will give different products. $- C H_{3}$ group will get oxdised to $- C O O H$ .

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Similar questions

Q. A coordination compound X gives pale yellow colour with

A g N O_{3}

solution while its isomer Y gives white precipitate with

B a C l_{2}

. Two compounds are isomers of

C o B r S O_{4}

5 N H_{3}

. What could be the possible formula of X and Y?

Q. An aromatic hydrocarbon has the molecular formula

C_{10} H_{14}

. Upon oxidation with boiling alkaline

K M n O_{4}

followed by acidification, it yields benzene dicarboxylic acid. The total isomers for

C_{10} H_{14}

are:

Q. The number of aromatic isomers possible for

C_{7} H_{8} O

Q. The octahedral complex

C o S O_{4} C l_{5} N H_{3}

exists in two isomeric forms

X

and

Y

. Isomers

X

reacts with

A g N O_{3}

to give a white precipitate, but does not react with

B a C l_{2}

. Isomer

Y

gives white precipitate with

B a C l_{2}

but does not react with

A g N O_{3}

.
Isomers

X

and

Y

are:

Q. The octahedral complex

C o S O_{4} C l .5 N H_{3}

exists in two isomeric forms X and Y. Isomer X reacts with

A g N O_{3}

to give a white precipitate, but does not react with

B a C l_{2}

. Isomer Y gives white precipitate with

B a C l_{2}

but does not react with

A g N O_{3}

. Isomer X and Y are

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An aromatic compound has molecular formula C7H7Br. Give the possible isomers and the appropriate method to distinguish them

The correct option is C 4 isomers; by oxidationFour isomers are possible. They can be separated by oxidation. Different isomers will give different products. −CH3 group will get oxdised to −COOH.

An aromatic compound has molecular formula $C_{7} H_{7} B r$ . Give the possible isomers and the appropriate method to distinguish them

The correct option is C 4 isomers; by oxidation
Four isomers are possible. They can be separated by oxidation. Different isomers will give different products. $- C H_{3}$ group will get oxdised to $- C O O H$ .