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Standard XII

Chemistry

Hydroboration Oxidation

An aromatic c...

Question

An aromatic compound X, $C_{7} H_{7} C l$ on oxidation gives an aromatic compound Y. The soda-lime decarboxylation of Y gives benzene. X is

O – Cholorotoluene

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P – Cholorotoluene

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Benzyl Chloride

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M – Cholorotaluene

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Solution

The correct option is C Benzyl Chloride
$C H_{6} H_{5} C H_{2} C l O \to C_{6} H_{5} C O O H N a O H - --- \to C a O C_{6} H_{6}$
Benzylchloride

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An aromatic compound X, C7H7Cl on oxidation gives an aromatic compound Y. The soda-lime decarboxylation of Y gives benzene. X is

The correct option is C Benzyl ChlorideCH6H5CH2ClO→C6H5COOHNaOH−−−−→CaOC6H6 Benzylchloride

An aromatic compound X, $C_{7} H_{7} C l$ on oxidation gives an aromatic compound Y. The soda-lime decarboxylation of Y gives benzene. X is

The correct option is C Benzyl Chloride
$C H_{6} H_{5} C H_{2} C l O \to C_{6} H_{5} C O O H N a O H - --- \to C a O C_{6} H_{6}$
Benzylchloride