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Physics

Critical Angle

An arrangemen...

Question

An arrangement for YDSE is shown in figure. S is a light source then find the position of central maxima from point O on screen B.

5 mm below O

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5 mm above O

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30 mm below O

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\infty

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Solution

The correct option is D $\infty$
$\begin{matrix} x = \frac{Δ d}{w} = \frac{Δ \times 3 m}{1} = Δ 3 m m \Rightarrow \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \Rightarrow \frac{1}{v} + \frac{1}{20} = \frac{1}{20} ∴ v = \infty \end{matrix}$
Hence,
Option $D$ is correct answer.

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An arrangement for YDSE is shown in figure. S is a light source then find the position of central maxima from point O on screen B.

The correct option is D ∞x=Δdw=Δ×3m1=Δ3mm⇒1v−1u=1f⇒1v+120=120∴v=∞Hence,Option D is correct answer.

The correct option is D $\infty$
$\begin{matrix} x = \frac{Δ d}{w} = \frac{Δ \times 3 m}{1} = Δ 3 m m \Rightarrow \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \Rightarrow \frac{1}{v} + \frac{1}{20} = \frac{1}{20} ∴ v = \infty \end{matrix}$
Hence,
Option $D$ is correct answer.