Question

An arrow is projected into air. It's time of flight is $5seconds$ and range $200m$. What is the maximum height reached by it ? Take $(g=10m/s^2$)

• A. $31.25m$
• B. $46.75m$
• C. $24.50m$
• D. $18.25m$

Answer 1

The correct option is A $31.25m$

Range is there so the arrow was projected at some $angle$, let it is $\theta$

then time of flight $T=\frac{2uSin\theta }{g}=5$

and range $R=\frac{u^{2}2Sin\theta Cos\theta }{g}=200$

we get $\frac{R}{T}=\frac{200}{5}=\frac{uCos\theta }{1}$ or $uCos\theta =40m/s$

putting it in the expression of $R$ we get $\frac{2uSin\theta }{g}=\frac{200}{40}=5$ or $usin\theta =25m/s$

so max height will be $H=\frac{(uSin\theta {)}^2}{2g}=\frac{625}{20}=31.25meter$