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Motion Under Gravity

An arrow is t...

Question

An arrow is thrown in the air it's time of flight is 5 second and the range is 200 m. Determine( a )the vertical component of the velocity of projection (b)the horizontal component (c) maximum height (d) the angle made with the horizontal.(g= 9.8m/s^2₎

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Solution

Equation for tine oof flight=2u/g=t

So u=tg/2
=5×9.8/2
=49/2
=24.5

So answer for a)is 24.5

Now for maximum hegut hmax=u²/2g
=24.5²/2*9.8
=30.625.

Now answer for d is angle made with horizontal is
24.5/40
tan-¹=49/80=24.5/40

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