A trader bought a number of articles for Rs. 1,200. Ten were damaged and he sold each of the remaining articles at Rs. 2 more than what he paid for it, thus getting a profit of Rs. 60 on the whole transaction ?

Taking the number of articles he bought as x, form an equation in x and solve it.

Q. Bashir bought an article for

R s 1215

and spent

R s 35

on its transportation. At what price should he sell the article to gain

16 %

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An article is marked at Rs 18,000. A trader bought it at successive discounts of 25% and 10% respectively. He spent Rs 1,350 on its transportation to his shop and then sold the article for Rs 15,000. What is trader's profit% in the whole transaction?

The correct option is D 1119%He bought the article for [(100−25)100][(100−10)100]×18000=12,150 Spent 1350 on repairs, Total CP = 1350 + 12150 = 13,500 SP = 15,000 So profit%=150013500×100=1119%

The correct option is D $11 \frac{1}{9} %$
He bought the article for
$[\frac{(100 - 25)}{100}] [\frac{(100 - 10)}{100}] \times 18000 = 12, 150$
Spent 1350 on repairs,
Total CP = 1350 + 12150 = 13,500
SP = 15,000
$S o p r o f i t % = \frac{1500}{13500} \times 100 = 11 \frac{1}{9} %$