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Question

An article manufactured by a company consists of two parts X and Y. In the process of manufacture of part X, 9 out of 104 parts may be defective. Similartly, 5 out of 100 are likely to be defective in the manufacture of the part Y. Calculate the probability that the assembled product will not be defective.


A

360416

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B

331416

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C

361416

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D

324416

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Solution

The correct option is C

361416


Since in the process of manufacture fo part X, 9 out of 104 part may be defective, therefore the probability of x to be defective=9104 and
its not being defective =1(9104)=95104.
Similartly the probability of the part Y to be defective =5100=120and
not to be defective
=1(120)=1920
Now the assembled product will not be defective if both the parts are not defective and hence the probability of this event
=95104×1920=19×19104×4=361416.
[By the multiplication therorem.]


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