Solving a Quadratic Equation by Factorization Method
An article wa...
Question
An article was sold at 25% loss. Had the article been sold for Rs.60 more there would have been a profit 5%. Find the cost price of the article.
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Solution
(i) Suppose the cost price of the article is Rs.100 at loss of 25% the S.P of the article is Rs.(100−25)=Rs.75. At profit of 5% the S.P of the article is Rs.(100+5)=Rs.105 ∴ The difference of the two S.Ps is Rs.105−75=Rs.30 If the C.P is Rs.100, The difference in the two S.Ps is Rs.60 then the C.P is 10030×60=Rs.200 (ii) Suppose the cost price of article is x At 25% loss,
S.P =x−25x100=75x100=Rs.34x At 5% profit, S.P=x+5x100=105100x=Rs.2120x Accordingly, 2120x−34x=60
⇒21x−15x20=60 ⇒6x20=60
⇒x=60×206=200 ∴ The cost price of article is Rs.200.