Let the mass of satellite be 'm' and the mass and radius of earth be M,R respectively.
V is the velocity of the satellite relative to earth
In an earth's orbit, centripetal force is equal to gravitational pull of the earth.
⇒GMm(R+h)2=mv2R+h⇒(R+h)=GMv2⇒h=GMv2−R
But, g=GMR2
Therefore, ⇒h=gR2v2−R∴h=R(gRv2−1)
Hence, x=1