wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An artificial satellite is moving around earth in a circular orbit with speed equal to one fourth the escape speed of a body. From the surface of earth the hight of satellite above earth's surface is (R = radius of earth)

Open in App
Solution

We know that,

Escape velocity = 2gR

Given, Orbital speed of satellite = 2gR4

By force balance we have,

Gravitational force = Centripetal force

GMmx2=mv2x

x=GMv2=GM2gR×16=8GMGMR2×R=8R

Height of satellite above earth's surface is 8RR=7R.


flag
Suggest Corrections
thumbs-up
39
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon