An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the Earth.

2.07 km/s

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3.07 km/s

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4.21 km/s

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1.28 km/s

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Solution

The correct option is B
3.07 km/s

The distance covered by the satellite in 24 hours is the circumference of the circular orbit.
Speed $= \frac{C i r c u m f e r e n c e o f o r b i t}{T i m e p e r i o d}$

$= \frac{2 π R}{T}$

$= \frac{2 \times π \times 42250}{24 \times 3600}$ $\frac{k m}{s}$
$[∵ 1 h r = 60 \times 60 = 3600 s]$

$= 3.07 \frac{k m}{s}$

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