Question

An artificial satellite is moving in a circular orbit of radius $8400km$ around the earth. What is its speed if it takes one day to complete one revolution?
[1 Mark]

Answer 1

Given, the radius of the orbit, $R=8400km$
The time taken to revolve around the Earth, $T=24hr\left(1day\right)$
The speed of the satellite, $v=\frac{\text{Circumference of the orbit}}{\text{Time taken}}$
$=\frac{2\pi R}{T}$
$=\frac{2\times 3.14\times 8400\text{km}}{24\text{hr}}$
$=2198\text{km}{\text{hr}}^{-1}$
$=2198\text{kmph}$
[1 Marks]