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Question

An artificial satellite is revolving round the earth in a circular orbit. Its velocity is half the escape velocity. Its height from earth's surface is

A
6400 km
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B
12800 km
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C
3200 km
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D
1600 km
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Solution

The correct option is A 6400 km
Orbital velocity of the artificial satellite
v0=RgR+h
Escape velocity vc=2gR
Given, v0=12vc
122gR=RgR+h
12=RR+h
or R+h=2R
h=R=6400 km.

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