An artificial transmutation was carried out on $_{7}^{14} N$ by an $α$ -particle which resulted in an unstable nuclide and a proton. What is the ratio of the atomic mass to the atomic number of the unstable nuclide?

\frac{17}{8}

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\frac{15}{7}

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\frac{17}{9}

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\frac{15}{8}

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Solution

The correct option is A $\frac{17}{8}$
$_{7}^{14} N +_{2}^{4} H e ⟶$ $_{8}^{17} O +_{1}^{1} H$
$\frac{M a s s N u m b e r}{A t o m i c N u m b e r} = \frac{17}{8}$

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An artificial transmutation was carried out on 147N by an α-particle which resulted in an unstable nuclide and a proton. What is the ratio of the atomic mass to the atomic number of the unstable nuclide?

The correct option is A 178147N+42He⟶ 178O+11HMassNumberAtomicNumber=178

An artificial transmutation was carried out on $_{7}^{14} N$ by an $α$ -particle which resulted in an unstable nuclide and a proton. What is the ratio of the atomic mass to the atomic number of the unstable nuclide?

The correct option is A $\frac{17}{8}$
$_{7}^{14} N +_{2}^{4} H e ⟶$ $_{8}^{17} O +_{1}^{1} H$
$\frac{M a s s N u m b e r}{A t o m i c N u m b e r} = \frac{17}{8}$